Part A What is the value of the bond angle in CCl4? enter the bond angle of the molecule. Component B What is the value of the smallest bond edge in ClF4- ? get in the smallest bond edge of the molecule. Component C What is the worth of the bond angle in COH2? enter the bond angle of the molecule. Component D What is the value of the bond angle in ICl2- ? go into the bond edge of the molecule.

The principle used to solve this problem is based on the Valence covering Electron Pair Repulsion theory.

The VSEPR theory is supplied to suspect the form of the molecule through the assist of number of electrons pair bordering the main metal atom.

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By predicting the form of molecule, bond can be predicted.


For predicting the form of molecule by utilizing VSEPR theory, that is crucial to attract Lewis framework of the molecule.

Lewis structure deserve to be attracted by count the total number of valence electrons in the molecule. The rules for drawing Lewis structure room as follow.

First write the structure of the link by placing bonding atoms beside each other. The the very least electronegative atom rectal the central position.

Count the total number of valence electron in the molecule. Include the number of an unfavorable charge come the total variety of valence electrons and subtract the number of positive fee from total number of valence electrons.

Complete the octets the the atoms bonded to central atom.


(1)

The atomic number of chlorine and carbonare17 and6. The number of valence electron presentare 7 and 4 respectively. Yet there are 4chlorine atoms. So, total number of valence electron in chlorine room 28. Thus, total number of valence electrons room 32. This electrons are distributed in together a method that every atom has finish octet.

The Lewis framework of CCl4\rmCC\rml_4CCl4​ is attracted as follows:

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Now, according to the VSEPR theory, the molecule with main atom bonded to 4 electron groups has the tetrahedral shape. For tetrahedral shape, the shortcut angles between atoms room 109.5∘109.5^ \circ 109.5∘ .

(2)

The atomic number of chlorine and also fluorine space 17 and 9. The number of valence electrons existing in both atoms are 7. However there space 4 fluorine atoms. So, total variety of valence electron in fluorine room 28. Also, over there is a negative charge. Thus, total number of valence electrons are 36. This electrons are distributed in together a way that every atom has complete octet.

The Lewis structure of ClF4−\rmClF_4^ - ClF4−​ is attracted as follows:

*

Now, according to the VSEPR theory, the molecule with main atom bonded to six electron teams has the square planar shape. For square planar shape, the shortcut angles in between atoms space 90∘90^ \circ 90∘ .

(3)

The atomic variety of carbon and also oxygen space 6 and also 8. The number of valence electrons current are 4 and 6 respectively.Also, there are two hydrogen atoms. Thus, total number of valence electrons room 12. This electrons are spread in together a way that every atom has finish octet.

The Lewis framework of COH2\rmCO\rmH_2COH2​ is attracted as follows:

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Now, according to the VSEPR theory, the molecule with central atom bonded to 3 electron teams has the trigonal planar shape. Because that trigonal planar shape, the shortcut angles in between atoms room 120∘120^ \circ 120∘ .

(4)

The number of valence electrons present in iodine and chlorine room 7 and 7 respectively. Yet there room two chlorine atoms. Thus, total number of valence electrons are 22. This electrons are spread in together a means that every atom has complete octet.

The Lewis structure of ICl2−\rmICl_2^ - ICl2−​ is attracted as follows:

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Now, according to the VSEPR theory, the molecule with central atom external inspection to 5 electron teams has the linear shape. For straight shape, the shortcut angles between atoms are 180∘180^ \circ 180∘ .

Ans: component 1

The bond angle of CCl4\rmCC\rml_4CCl4​ molecule is 109.5∘109.5^ \circ 109.5∘ .

Part 2

The bond edge of ClF4−\rmClF_4^ - ClF4−​ molecule is 90∘90^ \circ 90∘ .

Part 3

The bond angle of COH2\rmCO\rmH_2COH2​ molecule is 120∘120^ \circ 120∘ .

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Part 4

The bond angle of ICl2−\rmICl_2^ - ICl2−​ molecule is 180∘180^ \circ 180∘ .